lim x mendekati 1 sin(tx-π)/ (1-x)
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Penjelasan dengan langkah-langkah:
[tex] = \lim \limits_{x \to1} \frac{ \sin(\pi x - \pi) }{1 - x} [/tex]
[tex] = \lim \limits_{x \to1} \frac{ \sin( - \pi + \pi x) }{1 - x} [/tex]
[tex] = \lim \limits_{x \to1} \frac{ \sin( - \pi(1 - x)) }{1 - x} [/tex]
[tex] = \lim \limits_{u \to0} \frac{ \sin( - \pi u) }{u} [/tex]
[tex] = - \pi[/tex]
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